X^2-10x-416=0

Solution for X^2-10x-416=0 equation:

X^2-10X-416=0

a = 1; b = -10; c = -416;
Δ = b2-4ac
Δ = -102-4·1·(-416)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-42}{2*1}=\frac{-32}{2}
=-16
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+42}{2*1}=\frac{52}{2}
=26
$